美国科学技术学院2015年单招英语真题及答案解析及解析

美国科学技术学院2015年单招英语真题及答案解析及解析

好的c 五子棋游戏设计硬件设备,下面是一个简单的五子棋Python代码示例:```pythonimport numpy as np# 初始化棋盘大小和棋子类型BOARD_SIZE = 15 # 棋盘大小BLACK = 1 # 黑棋WHITE = 2 # 白棋# 初始化一个空棋盘board = np.zeros((BOARD_SIZE, BOARD_SIZE))# 定义棋盘落子函数def move(board, x, y, player):board[x][y] = player# 定义判断胜利条件的函数def check_win(board, player):# 横向判断for i in range(BOARD_SIZE):for j in range(BOARD_SIZE - 4):if board[i][j] == player and board[i][j+1] == player and board[i][j+2] == player and board[i][j+3] == player and board[i][j+4] == player:return True# 竖向判断for i in range(BOARD_SIZE - 4):for j in range(BOARD_SIZE):if board[i][j] == player and board[i+1][j] == player and board[i+2][j] == player and board[i+3][j] == player and board[i+4][j] == player:return True# 左上到右下判断for i in range(BOARD_SIZE - 4):for j in range(BOARD_SIZE - 4):if board[i][j] == player and board[i+1][j+1] == player and board[i+2][j+2] == player and board[i+3][j+3] == player and board[i+4][j+4] == player:return True# 右上到左下判断for i in range(BOARD_SIZE - 4):for j in range(4, BOARD_SIZE):if board[i][j] == player and board[i+1][j-1] == player and board[i+2][j-2] == player and board[i+3][j-3] == player and board[i+4][j-4] == player:return Truereturn False# 测试代码move(board, 7, 7, BLACK)move(board, 7, 8, WHITE)move(board, 8, 7, BLACK)move(board, 8, 8, WHITE)move(board, 9, 7, BLACK)print(board)print(check_win(board, BLACK)) # Trueprint(check_win(board, WHITE)) # False```这段代码实现了一个简单的五子棋游戏。其中c 五子棋游戏设计,`board`代表棋盘,`move()`函数用于落子游戏图片素材,`check_win()`函数用于判断胜利条件。您可以自行调整落子位置,测试代码的效果。

文章来源:https://blog.csdn.net/qq_26369213/article/details/45936191